Mathematics, 01.08.2020 19:01 jdkrisdaimcc11
Suppose babies born in a large hospital have a mean weight of 3366 grams, and a variance of 244,036. 1118 babies are sampled at random from the hospital what is the probability that the mean weight of the sample babies would be greater than 3412 gram answer to four decimal places Round your
Answers: 3
and 
be the sample mean weight of babies.![P(\overline{X}3412)=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\dfrac{3412-3366}{\dfrac{494}{\sqrt{1118}}})\\\\=P(Z\dfrac{46}{14.7743})\ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\\approxP(Z3.11)\\\\= 1-P(Z](/tpl/images/0716/4601/bc3c1.png)
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Suppose babies born in a large hospital have a mean weight of 3366 grams, and a variance of 244,036....
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