In 2012, entering freshmen at the UA have an average ACT score of 25.4 with a standard deviation of 2.1. 1. What is the probability a student has an ACT score more than 24.1

 P [ Z >  24,1 ] =  72,24 %

Step-by-step explanation:

P [ Z > 24,1 ]  =  1  - P [ Z < 24,1 ]

P [ Z < 24,1 ] = ( Z - μ₀ ) / σ

P [ Z < 24,1 ] = ( 24,1 - 25,4) / 2,1

P [ Z < 24,1 ] = - 1,3/ 2,1

P [ Z <  24,1 ] = - 0,6190  ≈ - 0,62

We look in z-table and find for  z(score) -0,6190

P [ Z <  24,1 ] = 0,27763

Then

P [ Z >  24,1 ] = 1 - 0,27763

P [ Z >  24,1 ] = 0,72237    ⇒    or       P [ Z >  24,1 ] =  72,24 %

ab will be equal to

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: