(Slope question!) Please help me:)

A

Step-by-step explanation:

We know that (15, 11) (which means x = 15, y = 11) is a solution to Line Q so therefore:

11 = 4/3 * 15 + (k + 1)

11 = 21 + k

k = -10

-10 = k

Step-by-step explanation:

y = 4/3x + ( k+1)

We know a point on the line is ( 15,11)

Substitute this point into the equation

11 = 4/3(15) + (k+1)

11 = 20 + k+1

Combine terms

11 = 21+k

Subtract 21 from each side

11-21 = k

-10 = k

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.