The mean of normally distributed test scores is 82 and the standard deviation is 5. If there are 241 test scores in the data sample, how many of them were in the 92 to 97 range?

5

Step-by-step explanation:

Find the z-scores.

z = (x − μ) / σ

z₁ = (92 − 82) / 5

z₁ = 2

z₁ = (97 − 82) / 5

z₂ = 3

Find the probability:

P(92 < X < 97)

P(2 < Z < 3)

P(Z < 3) − P(Z < 2)

0.9987 − 0.9772

0.0215

Find the number of tests:

0.0215 (241) ≈ 5

step-by-step explanation:

from the graph attached below:

domain of graph is the value of x for which the given function profit function p(x) is defined.

(a) the domain represents the number of years for which the outlet will earn a profit.

range of profit function defines the lowest to highest value of profit earned.

(b) the range of this function is (0 , 160 ). for this function, the range represents the outlet's profit earned.