"Use what you know about zeros of a function and end behavior of a graph that matches the function f(x)=(x-3)(x-2)(x+1)." Choices below:

Explanation:

The x intercepts here are -1, 2 and 3. This is where the graph crosses the x axis. We can determine these three values by solving f(x) = 0.

In other words, set (x-3)(x-2)(x+1) equal to zero and solve for x.

(x-3)(x-2)(x+1) = 0

x-3 = 0 or x-2 = 0 or x+1 = 0

x = 3 or x = 2 or x = -1

x = -1 or x = 2 or x = 3

When we expand out (x-3)(x-2)(x+1), there will only be one x^3 term and the coefficient for this term is positive 1. The positive leading coefficient indicates that the graph goes up forever as we move to the right. In other words, the graph grows forever after passing that dip between x = 2 and x = 3.

Another way you could phrase it is that "as x goes to infinity, y also goes to infinity". An informal way is to say "the graph rises to the right" to describe the end behavior.

here

step-by-step explanation:

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes