Identify the zeros of f(x)= (x-7)(x+4)(3x-2) Choices:

second option

Step-by-step explanation:

Given

f(x) = (x - 7)(x + 4)(3x - 2)

To find the zeros let f(x) = 0, that is

(x - 7)(x + 4)(3x - 2) = 0

Equate each factor to zero and solve for x

x - 7 = 0 ⇒ x = 7

x + 4 = 0 ⇒ x = - 4

3x - 2 = 0 ⇒ 3x = 2 ⇒ x =

zeros are x = - 4, x = , x = 7

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step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb