One positive integer is 6 less than twice another. The sum of their squares is 801. Find the integers

Step-by-step explanation:

Hello,

We can write the following, x being the second number.

Let's use the discriminant.

There are two solutions and the positive one is

So the solutions are 15 and 15*2-6 = 30-6 = 24

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation: