A una granja llegaron 54 ovejas 24 vacas 30 cerdos los cuales se quieren repartir en corrales con igual numero de animales de forma que haya la mayor cantidad posible en cada corral ¿cuantos animales posibles deben ir en cada uno de los corrales?

6 animals should go in each pen.

Step-by-step explanation:

Total sheep = 54

Total cows = 24

Total pigs = 30

Highest number of animals are possible in each pen such that animals are distributed in pens with the same number = Greatest common divisior (54,24, 30)

54= 6 x 9

24= 6 x 4

30 = 6 x 5

So, Greatest common divisior (54,24, 30) = 6

Hence, 6 animals should go in each pen.

i would need to see the dot plot : )

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral