Factor the trinomial.
x2+11x+24

(x + 3)(x + 8)

Step-by-step explanation:

We're looking for two numbers that have a sum of 11 and product of 24; these numbers are 3 and 8 so the factored form is (x + 3)(x + 8).

(x + 8)(x + 3)

Step-by-step explanation:

Hey there!

Well in the polynomial,

x^2+11x+24

we need to find out what*what = 24

8*3 = 24

8x + 3x = 11x

x*x = x^2

Factored (x + 8)(x + 3)

Hope this helps :)

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240