Find the surface area of the cone represented by the net below. 31.4 in.2
43.96 in.2
394.38 in.2
56.52 in.2

  43.96 in^2

Step-by-step explanation:

The net shows the areas of the parts of the cone, so you simply need to add them up to get the total surface area.

  31.4 in^2 +12.56 in^2 = 43.96 in^2

43.96 in.2.

Step-by-step explanation:

The surface area of a cone is the triangular shape and its circular base.

In this case, the top of the cone is 31.4 inches squared in area, and the circular base is 12.56 inches squared.

So, the surface area of the cone is 31.4 + 12.56 = 43.96 inches squared.

Hope this helps!

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.