Help!! I WILL GIVE BRAINLIEST I NEED HELP PLEASE PLEASE PLEASE PLEASE IM DEADD I REALLY NEED HELP ASAP ITS URGENT

arc axb=4.938

Step-by-step explanation:

to find the  measure of arc AXB find angle P first

length of the arc=rФ

in triangle APQ sin angle APQ= opp/hyp=AQ(radius)/PQ=5/√5+√21

in traingle PQB sin angle BPQ= opp/hyp.=5/√5+√21

angle P"

2arcsin 5/√5+√21= 94.324 degrees=(π*94.324)/180=1.64626 rad.

arc AXB=Фr (Ф=94.324 , r=3)

arc axb=4.938

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

hi how are you doing today? if you ever need just tell me

step-by-step explanation: