Find the first four terms of the sequence given a1=31 and an+1=an−3

Step-by-step explanation:

Given the formula

a(n+1)=an−3

The first term a(1) = 31

For the second term

a(2)

We have

a( 1 + 1) = a(1) - 3

a(2) = 31 - 3

a(2) = 28

For the third term

a(3)

We have

a(2+1) = a(2) - 3

a(3) = 28 - 3

a(3) = 25

For the fourth term

a(4)

That's

a(3+1) = a(3) - 3

a(4) = 25 - 3

a(4) = 22

Hope this helps you

answer: a

step-by-step explanation:

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )