a sinusoid always function has an amplitude of 3, a frequency of 1/8pi, and a midline at 2. Which of the following equations satisfies these conditions? a. f(x)=3sin x/8pi +2 b. f(x)=3sin(4x) +2 c. f(x)=3sin(8pi x) +2 d. f(x)=3sin x/4 +2

The correct option is;

f(x) = 3·sin x/8·π + 2

Step-by-step explanation:

The given parameters for the sinusoidal function are;

Amplitude of oscillation = 3

Frequency of oscillation = 1/8·π

Midline of oscillation= 2

The general form of sinusoidal equation is y = A·sin(B(x - C)) + D

Where;

A = The amplitude

B = The frequency

C = The horizontal shift

D = The midline or vertical shift

Substituting the given values into the general form of sinusoidal equation, we have;

f(x) = y =  3·sin(1/8·π(x - 0)) + 2 = 3·sin(x/8·π) + 2

Which gives;

f(x) = 3·sin(x/8·π) + 2.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3