An observer (O) spots a bird flying at a 35° angle from a line drawn horizontal to its nest. If the distance from the observer (O) to the bird (B) is 21,000 ft., how far is the bird (B) from its nest (N)? Round to the nearest whole number. (4 points) A right triangle B N O is shown with angle B marked 35 degrees, side B N marked x and side B O marked 21000 feet. 14,704 feet 16,980 feet 17,202 feet 12,045 feet

The correct option is;

17,202 feet

Step-by-step explanation:

The distance from the observer to the bird is given as 21,000 ft

The angle between the line of flight of the bird to the horizontal line from its nest = 35°

With the triangle BNO = A right triangle, we have;

The distance of the bird from its nest = Adjacent leg of the right triangle

The distance of the observer from the bird = Hypotenuse length

Which by trigonometric relations gives;

21,000×cos(35 degrees) = The distance of the bird from its nest = 17,202.2 feet ≈ 17,202 feet.

207/8 is the right

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b