Take a coin with P(H) = 1/n and toss it until you see (n +1) many H's for the first time. Let Xn be the number of times we observe two successive H's. For example, suppose n = 5, you wait for the sixth H, and the sequence of tosses are HHHTTHTTHH, then Xn = 3 because there are 3 times that we observe two successive H's. Required:a. Find lim P(Xn >= 2). n→ [infinity] b. Now suppose P(H) = 1/n^2 and, as before, toss it until you see (n +1) H's for the first time. Let Xn be the same as before. Find the exact expression of P(Xn = 0) and compute lim P(Xn = 0). n→ [infinity]