Jamar rolls a 6-sided number cube with the numbers 1 through 6 on it. What is the probability that he does not roll a prime number?

Step-by-step explanation:

In a 6 sided die, the numbers that are possible to be rolled are

1, 2, 3, 4, 5, and 6.

We know that the numbers 2, 3, and 5 are prime, while 1, 4, and 6 are not.

3 out of the 6 numbers are prime, therefore 3 out of the 6 numbers are not prime.

So the fraction is

This simplifies to .

Hope this helped!

1/2

Step-by-step explanation:

the prime numbers between 1 and 6 inclusive are:  2, 3, 5  (i.e 3 possible outcomes)

the non prime numbers are : 1, 4 and 6 (i.e 3 possible outcomes)

for each roll, the total number of possible outcomes is 6 (because its a 6-sided die)

P(does not roll a prime number) = P (rolls 1, 4 or 6)

= number of possible non-prime outcomes / total number of outcomes

= 3/6

= 1/2

question is incomplete.