The perpendicular distance of the point from x axis is 2 units and the perpendicular distance from y axis is 3 units. Write the co-ordinates of the if it lies in

Step-by-step explanation:

Given that :

the  perpendicular distance of the point from x axis = 2 units

the perpendicular distance from y axis is 3 units

The objective is to the write the coordinates of the points if it lies in

(i) | Quadrant  (ii) || Quadrant (iii) ||| Quadrant (iv) |v Quadrant

The position of a point in a plane is conveniently specified by the distances fro two perpendicular lines.The lines are called the x-axis and y-axis and their [point of intersection is called the origin.

The perpendicular distance from the y-axis is called the x- coordinate or abscissa and the perpendicular distance from x-axis is called the y-coordinate or ordinate,The  coordinate form an ordered pair with the abscissa written as first.

With that be said, So In the given question,

the  perpendicular distance of the point from x axis = 2 units

y coordinate = ±2

the perpendicular distance from y axis is 3 units

x coordinate = ±3

The ordered pair of the coordinates = ( ±3, ±2)

Therefore;

in | quadrant ; we have (3,2)   where  x and y are both on the positive axis

in || quadrant ; we have (-3,2)   x is on the negative axis and y is on the positive axis

In ||| quadrant ; we have (-3. -2) both x and y are on the negative axis

In |v quadrant ; we have ( 3, -2)  x is on the positive axis and y is on the negative axis.

where's the diagram?

step-by-step explanation:

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: