The sum of three consecutive numbers is 276. What is the smallest of these intengers?

91

Step-by-step explanation:

Let x be the smallest one:

● x is the first number

● x+1 is the second number

● x+2 is the third number

The sum of these numbers is 276

● x+(x+1)+(x+2) =276

● x+x+1+x+2 = 276

● 3x + 3 = 276

Substract 3 from both sides:

● 3x+3-3 = 276-3

● 3x = 273

Divide both sides by 3

● (3x)/3 = 273/3

● x = 91

So the smallest one is 91

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