The mean weight of newborn infants at a community hospital is 6.6 pounds. A sample of seven infants is randomly selected and their weights at birth are recorded as 9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds. Does the sample data show a significant increase in the average birthrate at a 5% level of significance? A. Fail to reject the null hypothesis and conclude the mean is 6.6 lb.
B. Reject the null hypothesis and conclude the mean is lower than 6.6 lb.
C. Reject the null hypothesis and conclude the mean is greater than 6.6 lb.
D. Cannot calculate because the population standard deviation is unknown

The correct option is  A

Step-by-step explanation:

From the question we are told that

    The  population is  

     The level of significance is

      The sample data is  9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds

The Null hypothesis is

 The Alternative hypothesis is  

The critical value of the level of significance obtained from the normal distribution table is

Generally the sample mean is mathematically evaluated as

substituting values

The standard deviation is mathematically evaluated as

substituting values

Generally the test statistic is mathematically evaluated as

substituting values

Looking at the value of  t and     we see that hence we fail to reject the null hypothesis

  What this implies is that there is no sufficient evidence to state that the sample data show as significant increase in the average birth rate

The conclusion is that the mean is  

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

hope to and hope that my answer is brainliest.(follow me )

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

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