What is the area of the object of 4 cm 18 cm x 7 cm x 10 cm and 8 cm

In Part 4.2.5 of the experiment, the expected magnification of the microscope is given by Lab Manual Equation 4.3: . Refer also to Fig. 4.4 for a definition of the components and distances used in Eq. 4.3. Suppose you obtain the following data. The distance between the object and the objective lens is 12 cm. The distance between the objective lens and the real, inverted image is 36 cm. The focal length of the eyepiece is 6 cm. When viewing the ruled screen (as described in Part 4.2.5), you observe 3 magnified, millimeter divisions filling the 87 mm width of the screen. What eye-to-object distance is consistent with this data?

Step-by-step explanation:

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.