Logan wants to mix an 18% acid solution with a 48% acid solution to get 15L of a 38% acid solution. How many liters of the 18% solution and how many liters of the 48% solution should be mixed?

5 gallons of 18% solution

10 gallons of 48% solution

Step-by-step explanation:

x = gallons of 18% solution

y = gallons of 48% solution

Total volume is:

x + y = 15

Total amount of fertilizer is:

0.18 x + 0.48 y = 0.38 (15)

Solve by substitution.

0.18 x + 0.48 (15 − x) = 0.38 (15)

0.18 x + 7.2 − 0.48 x = 5.7

0.3 x = 1.5

x = 5

y = 10

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

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step-by-step explanation: