Solve the triangle. A = 51°, b = 14, c = 6, I'll give 20 points

Step-by-step explanation:

We have that

A = 51°, b = 14, c = 6

step 1

find the value of a

Applying the law of cosines

a²=c²+b²-2*c*b*cos A

a²=6²+14²-2*6*14*cos 51> 126.27

a=11.2

we know that

The sum of the lengths of any two sides of a triangle is greater than the length of the third side.

we have

a=11.2

b=14

c=6

so

(a+b) > c> (11.2+14)=25.2

25.2 > 6> is not correct

therefore

the answer is the option

a. No triangles possible

I don't know if i am right sorry if this is wrong

b mark me branliest thx

step-by-step explanation:

i would be happy to . most people on would also love to i'm sure. if you just want someone who has done algebra before and want a little more personal relationship than just begging strangers for , i can certainly be of service. i do have college myself so i might not be 24/7.