Draw a line for the axis of symmetry of function f. Also mark the x-intercept(s), y-Intercept, and vertex of the function. f(x)= x^2- 4x-5
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10-
Line
8
6
4
2-
-10
-8

1) Please find attached the graph sowing the line of symmetry

The symmetry line is a vertical line passing through (2, -9)

2) The x-intercept are (5, 0) and (-1, 0)

The y-intercept is (0, -5)

The vertex is (2, -9)

Step-by-step explanation:

The given function is;

f(x) = x² - 4·x - 5

The data values are generated as follows;

x,          f(x)

-1,         0

-0.8,    -1.16

-0.6,    -2.24

-0.4,    -3.24

-0.2,    -4.16

0,         -5

0.2,      -5.76

0.4,      -6.44

0.6,     -7.04

0.8,     -7.56

1,         -8

1.2,      -8.36

1.4,      -8.64

1.6,      -8.84

1.8,      -8.96

2,        -9

2.2,     -8.96

2.4,      -8.84

2.6,     -8.64

2.8,     -8.36

3,        -8

3.2,     -7.56

3.4,     -7.04

3.6,     6.44

3.8,     -5.76

4,        -5

4.2,      -4.16

4.4,     -3.24

4.6,     -2.24

4.8,      -1.16

5,           0

The minimum is found from differentiating the function, f(x), with respect to x and looking for the zeros of the result  as follows;

f'(x) = 2·x -4

f'(x) = 0 = 2·x -4

x = 2

The y-coordinate gives; f(2) = 2² - 4×2 - 5 = -9

Therefore, the symmetry line is a vertical line passing through (2, -9)

The x-intercept is the point at which y = 0, therefore, from f(x) = x² - 4·x - 5, we have;

0 = x² - 4·x - 5 = (x - 5)·(x + 1)  

Therefore, the x-intercept are x = 5 or -1

The x-intercept are (5, 0) and (-1, 0)

The y-intercept occur at the point where the x value = 0, therefore, we have;

The y-intercept occur at y = f(0) = 0² - 4·0 - 5 = -5

The y-intercept is (0, -5)

Re-writing the  equation in vertex form y = a(x - h)² + k gives;

f(x) = x² - 4·x - 5 = 1·(x - 2)² - 9

Therefore, the vertex is (2, -9)

me! what did you put for this question?

step-by-step explanation:

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05