To evaluate the integral 0 (t1/3 − t2/3) dt −1 , first use the property of definite integrals, that is, b (f(x) + g(x)) dx a = b f(x) dx a + b g(x) dx. a Therefore, 0 (t1/3 − t2/3) dt −1 = 0 t1/ dt −1 ---Select--- 0 t /3 dt. −1

It says factor each expression 49x-28?

Someone answer this asap rn for ! a discount store’s prices are 25% lower than department store prices. the function c(x) = 0.75x can be used to determine the cost c, in dollars, of an item, where x is the department store price, in dollars. if the item has not sold in one month, the discount store takes an additional 20% off the discounted price and an additional $5 off the total purchase. the function d(y) = 0.80y - 5 can be used to find d, the cost, in dollars, of an item that has not been sold for a month, where y is the discount store price, in dollars. create a function d(c(x)) that represents the final price of an item when a costumer buys an item that has been in the discount store for a month. d(c(x)) =

Which expressions are equivalent to -7+3(-4e-3)? choose all answers that apply: choose all answers that apply: a -4(3e+4)? 4(3e+4) b 12e12e c none of the above