A sample proportion of 0.36 is found. to determine the margin of error for this statistic, a simulation of 100 trials is run, each with a sample size of 50 and a point estimate of 0.36.the minimum sample proportion from the simulation is 0.28, and the maximum sample proportion from the simulation is 0.40.the margin of error of the population proportion is found using half the range. what is the interval estimate of the true population proportion?

(0.30, 0.42)

Step-by-step explanation:

Given the following :

Sample proportion = 0.36

Minimum sample proportion from simulation = 0.28

Maximum sample proportion from simulation = 0.40

Therefore ;

Range = (maximum sample proportions from simulation - minimum sample proportion from simulation)

Range = 0.40 - 0.28 = 0.12

Interval estimate of true population = sample proportion ± 0.5 (range)

0.36 ± 0.5(12)

0.36 ± 0.06

(0.36 - 0.06), (0.36 + 0.06)

(0.30, 0.42)

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0