If 1 and -1 are the zeroes of the polynomial p(x) = ax 3 + x 2 − 2x + b, find the values of a and b

Step-by-step explanation:

p(x) = ax³ + x² - 2x + b

p(1) = a(1)³ + 1² - 2•1 + b = a + 1 - 2 + b = a + b - 1

a + b - 1 = 0  ⇒   b = 1 - a

p(-1) = a(-1)³ + (-1)² - 2(-1) + b = -a + 1 + 2 + b = - a + b + 3

- a + b + 3 = 0    ∧   b = 1 - a

- a + (1 - a) + 3 = 0

- a + 1 - a + 3 = 0

-2a + 4 = 0

-2a = -4

 a = 2

b = 1 - 2 = -1

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: