Isabelle bought some stationery.1/3 of them. Were pencils.5/8 of the remainder were erasers and the rest were rulers. The table shows the cost of each stationery, Pencil:$1.20,Eraser:$1,Ruler:$0.50. She spent a total of $169.50 on all the stationery. a)What fraction of the stationery bought was rulers? b)How much more did she spend one erasers than rulers?

1/4 ; $28.25

Step-by-step explanation:

Given the following :

Cost of stationeries:

Pencil:$1.20

Eraser:$1

Ruler:$0.50

Total : $169.50

Let total Stationeries purchased = t

Fraction of pencils = 1/3t

Remainder = t - 1/3 = 2/3t

Fraction of eraser = 5/8 of remainder

Thus ;

Fraction of eraser = 5/8 * (2/3)t= 10/24 = (5/12)t

Rest were ruler ;

(2/3)t - (5/12)t= (8 - 5)/12

= 3 / 12 = 1/4t

Fraction of rulers = 1/4

Amount spent on erasers:

(5/12) of the total cost of stationery

(5/12) * 169.50 = $70.625

B.) How much more did she spend on erasers than rulers

Amount spent on rulers :

(1/4) * $169.50 = $42.375

Take the difference :

$(70.625 - 42.375) = $28.25

costs the what? what is the cost of the pants?

step-by-step explanation:

if it is $10, then the price is 14.

take 40% of the cost, and then add the cost.

40% of 10 = 4

4+10 = 14.

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.