Write 11 numbers in a row so that the sum of any 3 consecutive numbers is negative, while the sum of all the numbers is positive.

Step-by-step explanation:

Hello, if I take the following

2, 2, -5, 2, 2, -5, 2, 2, -5, 2, 2

The sum is 8*2-5*3=16-15=1 > 0

and

2 + 2 -5 < 0

2 - 5 + 2 < 0

-5 + 2 + 2 < 0

2 + 2 -5 < 0

2 - 5 + 2 < 0

-5 + 2 + 2 < 0

2 + 2 -5 < 0

2 - 5 + 2 < 0

-5 + 2 + 2 < 0

2 + 2 -5 < 0

2 - 5 + 2 < 0

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

b

2

−

b

b

3

+

7

b

2

+

14

b

+

6

%

−

3

b

3

+

7

b

2

+

14

b

+

6

%

step-by-step explanation: