The graph of a linear system is shown

The coordinates of the point of intersection is (2, 7)

Step-by-step explanation:

From the graph, we have the two intersecting straight lines each described as follows;

The first straight line graph from the left, we have;

y-intercept = (0, 5), x-intercept = (-5, 0) therefore, the slope, m = (0 - 5)/(-5 - 0) = 1

The equation of the graph is slope-intercept form is y - 5 = 1×(x - 0)

Which gives;

y = x + 5(1)

The second lie graph has y-intercept  = (0, 9), x-intercept = (9, 0) therefore, the slope, m = (0 - 9)/(9 - 0) = -1

The equation of the graph in slope-intercept form is y - 9 = -1×(x - 0)

Which gives;

y = -x + 9(2)

To find the point of intersection, we equate equation (1) to equation (2), which are the y-value function of x, we have;

x + 5 = -x + 9

x + x  = 9 - 5

2·x = 4

x = 4/2 = 2

x = 2

From either equation (1) or equation (2), we can find the value of y as follows;

y = -x + 9, where x = 2 gives;

y = -2 + 9 = 9 - 2 = 7

y = 7

The coordinates of the point of intersection is (2, 7).

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0