Please help asap. I will give a thanks, rate your answer and mark the brainliest one too! The formula v^2 - u^2 = 2as is used to model a moving object, where: u= starting speed (m/s) v = final speed (m/s) a = acceleration (m/s²) s = distance travelled (m) A car stops at some traffic lights. It then accelerates at 2.3 m/s² until it reaches a speed of 13.6 m/s. Find the distance, s, that it has travelled since stopping at the lights. Give your answer correct to 1 decimal place.

s = 40.2 m

Step-by-step explanation:

It is given that,

Initial speed of the car, u = 0 m/s

Final speed of the car, v = 13.6 m/s

Acceleration of the car, a = 2.3 m/s²

We need to find the distance, s, that it has travelled since stopping at the lights. For this, we will use third equation of motion as :

s is distance

So, the distance covered by the car is 40.2 meters.

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)