Helen made a scale drawing of the middle school. The gym is 195 inches long in the drawing. The actual gym is 104 feet long. What scale did Helen use?

5 inches on the drawing = 32 actual inches

Step-by-step explanation:

195 inches

104 x 12 = 1248 inches

1/39

she used a scale of 5 inches to represent 32 inches actual length

Step-by-step explanation:

We are told that helen made the gym to be 195 inches long in the drawing.

Now, we are told that the actual length of the gym is 104 ft long.

Thus, converting to inches,

1ft = 12 inches

So, 104ft = 104 × 12 = 1248 inches

Which means that 194 inches represented 1248 inches.

So the scale is:

195:1248

Dividing both by a common factor of 39 to give a scale of (195/39):(1248/39)

This gives;

5:32

So she used a scale of 5 inches to represent 32 inches actual length

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation: