Which statements are true about the graph of the function f(x) = 6x – 4 + x2? Select two options. The vertex form of the function is f(x) = (x – 2)2 + 2. The vertex of the function is (–3, –13). The axis of symmetry for the function is x = 3. The graph increases over the interval (–3, infinity). The function does not cross the x-axis.

  B, D

Step-by-step explanation:

If you're going to make claims about the graph, it is helpful to see a graph (attached).

A) The vertex form of the function is f(x) = (x +3)^2 -13, not the one shown.

B) The vertex is (-3, -13). True

C) The axis of symmetry is x = -3, not the one given.

D) The graph increases for x > -3. True

E) The function crosses the x-axis at about x=-6.6 and x=0.6.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

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step-by-step explanation: