A portion of the graph of f(x) = −x2 − 10x − 21 is shown. Which of the following describes all solutions for f(x)? a partial parabola opening down and passing through negative 7 comma 0 and negative 3 comma zero with endpoints at negative 8 comma negative 5 and negative 2 comma negative 5 (x, −x2 − 10x − 21), where −7 ≤ x ≤ −3
(x, y), where −7 ≤ x ≤ −3
(x, −x2 − 10x − 21), where −8 ≤ x ≤ −2
(x, y) for all real numbers

see maths ncert ex 3.1

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see maths ncert ex 3.1

you will get this and can't know this then tag me

i will give you this is very easy question

so don't lose 10 points for it

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

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step-by-step explanation: