If you're good at angles of depression please help me and show full working out ty

  236.9 m

Step-by-step explanation:

Let x and y represent the distances to the near and far cars, respectively. You know from the definition of the tangent of an angle that ...

  tan(angle of depression) = building height/distance to car

  tan(10°39') = 150/x

  x = 150/tan(10°39')

and

  tan(8°15') = 150/y

  y = 150/tan(8°15')

The difference of these two distances is the distance between the cars:

  y - x = 150/tan(8°15') -150/tan(10°39')

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The minutes of arc can be converted to fractional degrees:

  15' = 15'/(60'/1°) = (15/60)° = 0.25°

  39' = 39'/(60'/1°) = (39/60)° = (13/20)° = 0.65°

So, the distance of interest is ...

  distance between cars = (150 m)(1/tan(8.25°) -1/tan(10.65°)) ≈ 236.86 m

The cars are about 236.9 meters apart.

7

step-by-step explanation:

yuo ned the activity or vertical angle of the form of 1,7 but 2,2 has a c4,2 as it verticie so i not have a car