Find three different numbers such that the HCF of each pair of these numbers is greater
than 1 but the HCF of all three numbers is 1.

[Hint: For instance, the numbers 6, 10 and
15 satisfy the conditions.]

6, 10, 15

15,21,35

35, 55, 77

77, 91, 143

143, 187, 221

I can go on forever

There are different possibilities

b.) divide by -5.

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.