This figure shows how to create a six-pointed star from twelve equilateral triangle tiles: [asy] size(7cm); pair cis(real magni, real argu) { return (magni*cos(argu*pi/180),magni*sin(a rgu*pi/180)); } for(int i=90;i<450;i+=60) { pair c=cis(1.2,i); path p=c-cis(1,i)--c-cis(1,i+120)--c-cis (1,i-120)--cycle; fill(p, orange+white); draw(p); pair c=cis(2.4,i); path p=c+cis(1,i)--c+cis(1,i+120)--c+cis (1,i-120)--cycle; fill(p, orange+white); draw(p); }; label("$\longrightarrow$",(4,0)); pair x=(8,0); real s=sqrt(3); path p=x+cis(s,0)--x+cis(3,30)--x+cis(s, 60)--x+cis(3,90)--x+cis(s,120)--x+c is(3,150)--x+cis(s,180)--x+cis(3,21 0)--x+cis(s,240)--x+cis(3,270)--x+c is(s,300)--x+cis(3,330)--cycle; fill(p, orange+white); draw(p); [/asy] If each of the original tiles has a perimeter of $10$ cm, what is the perimeter of the final star in cm?