![-3\left[\cos \left(\frac{-\pi }{4})\right+i\sin \left(\frac{-\pi }{4}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi }{2}\right)\right]](/tpl/images/0720/3450/68021.png)
![-6\sqrt{2}\left[\cos \left(\frac{-\pi }{4}+\frac{-\pi \:\:\:}{2}\right)+i\sin \left(\frac{-\pi \:}{4}+\frac{-\pi \:\:}{2}\right)\right]](/tpl/images/0720/3450/de5ff.png)
for both 
and 
)
= 
= 
- Therefore our solution is option a.Express the product of z1 and z2 in standard form given that and
...
Mathematics, 12.08.2020 09:01 rafaellazaro60pcw3w5
Express the product of z1 and z2 in standard form given that ![z_{1} = -3[cos(\frac{-\pi }{4} )+isin(\frac{-\pi }{4} )]](/tpl/images/1717/7962/94801.png)
and ![z_{2} = 2\sqrt{2} [cos(\frac{-\pi }{2} )+isin(\frac{-\pi }{2} )]](/tpl/images/1717/7962/489fb.png)
Answers: 3
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