Can you please help me with this question. the question is attached below

Hey there! I'm happy to help!

If 70% of the students are female, then 30% of the students are male. Of these, 85% graduated. Let's find 85% of 30%.

0.85(0.3)=0.255

This means that 25.5% of the students are graduating males.

We want to find the probability that one of the graduating males are picked from the group of graduating people. We have to find how many girls graduated to find the total percent of peole who graduated.

75% of females (70% graduated).

0.75(0.7)=0.525

So, 52.5% of students are graduating females.

We have 52.5% as graduating females and 25.5% are graduating males. We combine this, showing us that 78% of students graduated.

Now, we want to find the probability of picking a graduating male. 25.5% is what percent of 78%? When working with percents, is means equals. Let's say that our percent is p and solve.

0.255=0.78p

We flip the equation so p is on the left.

0.78p=0.255

Divide both sides by 0.78.

p≈0.33 (rounded to nearest hundredth)

Therefore, there is a 33% chance of picking a male from the graduating students.

Have a wonderful day! :D

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.