If S( 1, 2, 3, 4, 5,6 ) find the probability that a number chosen is more than 4

1/3

Step-by-step explanation:

The list of sample space's elements: {1, 2, 3, 4, 5, 6}

The number of elements in sample space: 6

The list of elements belonged to the event "choosing the number larger than 4": {5, 6}

The number of elements in the event: 2

Hence, the probability of event "choosing a number larger than 4":

P = number of event's elements/number of sample space's elements

  = 2/6

  = 1/3

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

a

b

d

step-by-step explanation: