Let x represent the number of short-sleeved shirts ordered and let y represent the number of long-sleeved shirts ordered. Which system of linear equations represents the situation? 5x + 10y = 100 and 5 x plus 10 y equals 100 and StartFraction one-third EndFraction x plus StartFraction one-half EndFraction y equals 1,750.x + StartFraction one-half EndFractiony = 1,750 5x + 10y = 1,750 and 5 x plus 10 y equals 1,750 and StartFraction one-third EndFraction x plus StartFraction one-half EndFraction y equals 100.x + y = 100 x + y = 100 and x plus y equals 100 and StartFraction one-third EndFraction x plus StartFraction one-half EndFraction y equals 1,750.x + y = 1,750 x + y = 1,750 and x plus y equals 1,750 and StartFraction one-third EndFraction x plus StartFraction one-half EndFraction y equals 100.x + y = 100

2 is the final ! : )

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

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step-by-step explanation: