The null and alternate hypotheses are: H0:μ≤0
H1:μ>0
The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.
Day 1 2 3 4
Day Shift 10 12 15 18
Afternoon shift 8 9 13 16
At the .005 significance level, can we conclude there are more defects produced on the day shift?
1. State the decision rule. Round your answer to 2 decimal places.
Reject
H0 if t>=
2. Compute the value of the test statistic. Round your answer to 3 decimal places.
Value of test statistic =

8496 cars

step-by-step explanation:

the system of inequalities is

step-by-step explanation:

step 1

find the equation of the dashed line

we have the points

(0,0) and (3,1)

the line passes through the origin, so, is a direct variation

find the slope

the equation of the dashed line is

the solution of the inequality a s the shaded area above the dashed line

therefore

the equation of the inequality a is

step 2

find the equation of the solid line

we have the points

(4,0) and (0,4)

find the slope

the equation of the solid line is

the solution of the inequality b s the shaded area below the solid line

therefore

the equation of the inequality b is

step 3

the system of inequalities is

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w