2.3 repeating as a fraction

First, we can write:

x = 2 . ¯ 3

Next, we can multiply each side by  10 giving:

10 x = 23 . ¯ 3

Then we can subtract each side of the first equation from each side of the second equation giving:

10 x − x = 23 .¯ 3 − 2 . ¯ 3

We can now solve for  x  as follows:

10 x − 1 x = ( 23 + 0 . ¯ 3 ) − ( 2 + 0 . ¯ 3 )  ( 10 − 1 ) x = 23 + 0 . ¯ 3 − 2 − 0 . ¯ 3  

9 x = ( 23 -2 ) + ( 0 . ¯ 3 − 0 . ¯ 3 )  

9 x = 21 + 0

9 x = 21

9 x /9 = 21 /9

9 x /9 = 3 × 7 /3 × 3

x = 3 × 7 /3 × 3

x = 7 /3

Hope this helps!

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step-by-step explanation:

1/4 because there is 4 grades.