3x + 4y = 14 x = 2y - 12 Which point satisfies both equations? A) (-2,-2) B) (-2,5) C) (-4,4) D) (2,2)

  B)  (-2, 5)

Step-by-step explanation:

Perhaps easiest is to try the points to see what works. You can also graph the equations or solve by any of several other means.

Trying the points

  A) 3(-2)+4(-2) = -6 -8 = -14 ≠ 14

  B) 3(-2) +4(5) = -6 +20 = 14; -2 = 2(5) -12 = 10 -12 . . . . true

  C) 3(-4) +4(4) = -12 +16 = 4 ≠ 14

  D) 3(2) +4(2) = 6 +8 = 14; 2(2) -12 = -8 ≠ -2

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Choice B ( -2, 5) is the only point that works in both equations.

x = -2

y = 5

then:

B) (-2,5)

Step-by-step explanation:

3x + 4y = 14

x = 2y - 12

from te firs equation:

3x = 14 - 4y

x = (14-4y)/3

then:

2y - 12 = (14-4y)/3

3(2y-12) = 14 - 4y

3*2y + 3*-12 = 14 - 4y

6y - 36 = -4y + 14

6y + 4y = 14 + 36

10y = 50

y = 50/10

y = 5

from the second equation:

x = 2y - 12

x = 2*5 - 12

x = 10 - 12

x = -2

Check:

from the first equatión:

3x + 4y = 14

3*-2 + 4*5 = 14

-6 + 20 = 14

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.