Find the x-intercept(s) of the equation: y =3x^2-3x-6 a. x-intercepts: (-1,0) and (2,0)

b. x-intercepts:(0,-3) and (0,2)

c. x-intercept: (-6,0)

d. x-intercept: (0,-6)

(2,0)    ( -1,0)

Step-by-step explanation:

y =3x^2-3x-6

Let y = 0 and solve for x to find the x intercepts

0 =3x^2-3x-6

Factor out a 3

0 =3(x^2-x-2)

Factor inside the parentheses

0 = 3( x-2) (x+1)

Using the zero product property

x-2 =0    x+1 = 0

x=2      x = -1

(2,0)    ( -1,0)

Step-by-step explanation:

The x-intercept(s) is when y = 0.

3x² - 3x - 6 = 0

Factor left side of the equation.

3(x + 1)(x - 2) = 0

Set factors equal to 0.

x + 1 = 0

x = -1

x - 2 = 0

x = 2

The x-intercepts are (-1, 0) and (2, 0).

answer: what is the question you're trying to ask?

step-by-step explanation: