Inscribed angles. I need answers asap, thank you!

60°

Step-by-step explanation:

The whole circunference is 360° from a central angle

so from an inscribed angle is 180°

notice that arc ABC + arc ADC make the whole circunference

so the inscribed angles that support those arc together must add to 180°

120°+b=180

b=60

from here we deduce that a cyclic quadrilateral (a quadrilateral that his points are on a circunference) oposite angles add up to 180

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.