You and your friend are playing a game. The two of you will continue to toss a coin until the sequence HH or TH shows up. If HH shows up first, you win. If TH shows up first, your friend wins. What is the probability of you winning?

The probability of friend A winning with HH = 1/4.

Step-by-step explanation:

The probability of an event, A is P(A) given by the relationship;

P(A) = (The number of required outcome)/(The number of possible outcomes)

The parameters given are;

The condition of friend A winning = Coin toss sequence HH shows up

The condition of friend B winning = Coin toss sequence TH shows up

The number of possible outcomes = TT, TH, HH, HT = 4

(TH and HT are taken as different for the game to be fair)

The number of required outcome = HH = 1

Therefore;

The probability of friend A winning with HH = 1/4.

b: |12 – x| ≤ 0.25

step-by-step explanation:      

let x be the possible lengths in inches, of the ribbons jaime cut.

we have been given that jaime is cutting strips of ribbon for a project. he tries to cut each piece to be 12 inches long, but sometimes he cuts it too long or too short by as much as 0.25 inch.  

we can represent this information in an inequality as:

by the definition of absolute value function we will get,

upon combining our inequalities we will get,

therefore, the inequality   describes all the possible lengths (x), in inches, of the ribbons jaime cut.

step-by-step explanation:

answer: im gonna go with milli

step-by-step explanation: