A Food Marketing Institute found that 31% of households spend more than $125 a week on groceries. Assume the population proportion is 0.31 and a simple random sample of 373 households is selected from the population. What is the probability that the sample proportion of households spending more than $125 a week is less than 0.33

0.7967

Step-by-step explanation:

We know that population proportion p=0.31.

We have to find P(phat<0.33).

Mean=p=0.31

standard deviation=0.024 (rounded to three decimal places)

Thus, the required probability that sample proportion of households spending more than $125 a week is less than 0.33 is 79.67%

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

answer: for each 3 girls there is 2 boys . 3: 2

hope this ! (:   mark me as brainliest if you can