Find the empirical formula of the compound containing 2.4 gram of carbon, 6.4 gram of oxygen and 0.2 gram of hydrogen *sorry its chemistry*

Empirical formula= COOH

Step-by-step explanation:

Molecular mass of the elements

Carbon= 12

Oxygen= 16

Hydrogen= 1

We divide the elements each with their molecular formula

Carbon= 2.4/12

Carbon= 0.2

Oxygen= 6.4/16

Oxygen= 0.4

Hydrogen= 0.2/1

Hydrogen= 0.2

Now we divide with the smallest result which is 0.2

Carbon= 0.2/0.2

Carbon = 1

Oxygen= 0.4/0.2

Oxygen= 2

Hydrogen= 0.2/0.2

Hydrogen= 1

So we have

Carbon 1, oxygen 2, hydrogen 1

Empirical formula= COOH

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.