What is the equation for a parabola with a focus at (2,2) and a directix of x=8

( y-5) ^2 =-12(x-2)

Step-by-step explanation:

focus at (2,2) and a directrix of x=8

Using the equation

( y-k) ^2 = 4p(x-k)

where ( h,k) is the vertex

The vertex is 1/2 way between the focus and the directrix

( 2+8)/2 , 2

5,2 is the vertex

( y-5) ^2 = 4p(x-2)

distance from the focus to the vertex and from the vertex to the directrix is  

| p|

2-5 = p

-3 = p

( y-5) ^2 = 4*-3(x-2)

( y-5) ^2 =-12(x-2)

if im undersanding the question correctly, its organized from 10

step-by-step explanation: