Please help The midpoint (x, y) and the end point (x2, y2) are known. Find (x1, Y1) using the midpoint formula.

a. (x1,y1) = (2x + x2, 2y+y2)

b. (x1,y1) = (2x - x2, 2y - y2)

c. (x1,y1) = (x + x2, y + y2)

d. (x1,y1) = (x - x2, y - y2)

Step-by-step explanation:

Hey,there!!!

Let's simply work with it,

We have,

One point is (x2,y2) and midpoint is(x,y).

Now, let's use midpoint formulae,

Now, let's equate with their corresponding elements we get,

now, 2x=x1+x2

or, x1=2x-x2

and

now,

2y = y1+y2

or, y1 = 2y-y2

Therefore, the answer is (x1,y1)= { (2x-x2),(2y-y2) }

Hope it helps...

i would pic false cause it goes down towards negative

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.